The Force Method
Remove the prop and it sags; push it back with the redundant; make the two cancel. That cancellation is the compatibility equation.
Skip to the animationRemove enough restraints to leave a determinate structure, compute how far it deflects at each removed restraint, then find the redundant forces that push those deflections back to what the real structure requires — usually zero.
The procedure
- 1Find the degree of indeterminacy,
D_s = r − 3externally, or the truss equivalent. - 2Choose redundants and remove them, leaving a stable released structure that is determinate.
- 3Compute Δ₀, the deflection at each released point under the real loads.
- 4Compute δᵢⱼ, the deflection at i caused by a *unit* redundant at j, with the real loads removed.
- 5Impose compatibility:
Δ₀ + Σ δᵢⱼ·Rⱼ = 0, and solve for the redundants. - 6Superpose, and finish with ordinary statics.
Both deflection calculations are on a *determinate* structure, which is why the unit load method had to come first. Nothing in the method is new — it is the earlier topics arranged to supply the equation statics could not.
Choosing the redundant
The choice is free provided the released structure remains stable — releasing the fixed support of a propped cantilever would leave a mechanism, which is not permitted.
Different valid choices give different arithmetic and the same final answer. A good choice makes the released structure something whose deflections you already know, such as a simple cantilever or a simply supported beam.
The compatibility equation
For one redundant: Δ₀ + R·δ₁₁ = 0, so R = −Δ₀/δ₁₁. For a propped cantilever under a uniform load this gives R = 3wL/8.
Note that EI cancels for a uniform member, so the redundant depends on geometry alone. It reappears the moment stiffness varies along the structure — which is why a haunched beam cannot be solved from a standard table.
With n redundants this becomes [δ]{R} + {Δ} = {0}. The flexibility matrix is symmetric by Maxwell's reciprocal theorem, which halves the coefficients you must compute and provides a check on the rest.
What it also handles
- Support settlement. Instead of setting the deflection to zero, set it to the known settlement. Everything else is unchanged.
- Temperature and lack of fit. These contribute to
Δ₀through the unit load method, exactly as before. - Prestress. A deliberate lack of fit, introduced to produce a chosen force distribution.
This is where indeterminate structures earn their reputation: settlement and temperature induce real stresses with no load applied at all, because the structure has nowhere to move to.
Force method against stiffness method
| Force (flexibility) | Displacement (stiffness) | |
|---|---|---|
| Unknowns | Redundant forces | Joint displacements |
| Count | Static indeterminacy | Kinematic indeterminacy |
| Needs a choice | Yes — which release | No |
| Suits | Hand calculation, low D_s | Computers, any size |
The force method usually has fewer unknowns, which suited hand calculation. But it requires judgement in choosing a release, and a poor choice makes the arithmetic much worse — judgement a computer does not have. The stiffness method is entirely mechanical, so it scales to a hundred thousand unknowns, which is why every analysis program is built on it.
The numbers you will be asked for
- Compatibility, one redundant
Δ₀ + R·δ₁₁ = 0
So R = −Δ₀/δ₁₁.
- General form
[δ]{R} + {Δ} = {0}
One equation per redundant; [δ] is symmetric.
- Flexibility coefficient
δᵢⱼ = deflection at i from a unit redundant at j
δᵢⱼ = δⱼᵢ by Maxwell.
- Propped cantilever, UDL
R = 3wL/8
EI cancels for a uniform member.
- With settlement
Δ₀ + R·δ₁₁ = Δ_settlement
The right-hand side is no longer zero.
Advantages and disadvantages
Advantages
- Fewer unknowns than the stiffness method for low degrees of indeterminacy.
- The redundant has a direct physical meaning you can sanity-check.
- Settlement, temperature and lack of fit are handled by changing one term.
- The flexibility matrix is symmetric, which halves the work and checks itself.
Disadvantages
- Requires choosing a release, and a bad choice makes the arithmetic far worse.
- Every coefficient needs a separate deflection calculation.
- Impractical beyond about three redundants by hand.
- Not mechanisable, which is why computers use the stiffness method instead.
Watch it work
Check yourself
question 1 / 4
One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.