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The Per-Unit System

A normalisation that looks like bookkeeping and is not — chosen correctly, it makes every transformer in the network disappear from the diagram.

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Per-unit expresses every quantity as a fraction of a chosen base, and if the base voltages are picked in the same ratio as each transformer's turns, the ideal transformer disappears — leaving the whole network as one continuous circuit with no referrals anywhere in it.

The problem it solves

A network runs from 400 V to 400 kV, and impedances refer across a transformer by the square of the turns ratio. The same ohmic value means completely different things at different levels, and every calculation crossing a transformer needs a referral that can be got wrong.

Choosing bases

Two bases are chosen freely — conventionally base MVA and base kV — and base current and base impedance follow. Base MVA is picked once for the whole system; base kV changes at every transformer, in the turns ratio.

That last choice is the point. With base voltages in the turns ratio, 1 p.u. on one side is 1 p.u. on the other, the ideal transformer vanishes, and only its leakage impedance remains in series.

Why the numbers become readable

QuantityTypical per-unit value
Healthy bus voltage0.95 – 1.05
Transformer impedance0.05 – 0.12
Generator subtransient reactance X″0.1 – 0.25
Generator synchronous reactance X_d1.0 – 2.0

Values cluster tightly, so an out-of-range result is visibly wrong without knowing which voltage level you are on. A result of 0.4 p.u. is obviously an error; a result of 52.8 kV requires context to judge.

Base conversion

Nameplate impedance is already per-unit — but on the equipment's own rating. A 20 MVA transformer at 11% becomes 55% on a 100 MVA system base. Converting bases is the one calculation per-unit does not remove, and it is where mistakes concentrate.

Three-phase conventions

  • Base kV is the line voltage, not the phase voltage.
  • Base MVA is the three-phase total, not per phase.
  • With those two choices, every √3 cancels and three-phase per-unit arithmetic looks exactly like single-phase.

Mixing line and phase bases is the classic error, and it shows up as a stray factor of √3 or 3 — large enough to notice, and easy to rationalise away if you are not expecting it.

What it does not fix

A delta-star transformer introduces a 30° phase shift that per-unit does not remove, and it matters for unbalanced fault studies using symmetrical components.

And because every base must be consistent across the network, one wrong base propagates silently through a whole study. The results still look plausible, which is exactly what makes that error dangerous.

The numbers you will be asked for

Per-unit value

X_pu = X_actual / X_base

Base impedance

Z_base = (kV_base)² / MVA_base

Base current

I_base = MVA_base / (√3 · kV_base)

Base conversion

Z_new = Z_old · (MVA_new/MVA_old) · (kV_old/kV_new)²

Fault level

MVA_fault = MVA_base / Z_pu

Watch it work

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Check yourself

question 1 / 4

One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

What is the real reason the per-unit system exists?
A 20 MVA transformer is marked 11%. What is its impedance on a 100 MVA system base?
In three-phase per-unit, what are the conventions for base kV and base MVA?
What does per-unit fail to remove from a delta-star transformer?

0 / 4

4 still unanswered — the dots above jump straight to them.