Type a branch, a subject or a topic — “round robin”, “paging”, “civil”.

Zener Diodes and Voltage Regulation

A diode operated in the region every other topic told you to avoid. It runs hottest at no load, which is the opposite of intuition.

Skip to the animation

A Zener diode is operated deliberately in reverse breakdown, where its voltage stays nearly constant over a wide range of current — making it a voltage reference, though a poor regulator, because its finite slope resistance and constant power dissipation both work against it.

Breakdown, used on purpose

Past the breakdown voltage, reverse current rises almost vertically while the voltage barely changes. For an ordinary diode that is destruction; a Zener is built to survive it, and that near-vertical characteristic is what a voltage reference needs.

Breakdown itself is non-destructive. Heat is what kills the device, so the current must always be limited by an external resistor.

Two mechanisms, one name

Zener breakdownAvalanche breakdown
Voltage rangeBelow about 5 VAbove about 5 V
MechanismField pulls carriers out of bondsCarriers accelerate and knock others loose
DopingHeavy, thin depletion regionLighter, wide region
Temperature coefficientNegativePositive

Around 5.6 V the two coefficients cancel, which is why precision voltage references cluster at that value.

The shunt regulator

A series resistor drops the surplus voltage and the Zener clamps what remains. The resistor's current splits between the load and the Zener, so the Zener absorbs whatever the load does not take — meaning it dissipates most at no load.

  1. 1At minimum input and maximum load, R_s must still leave the Zener its minimum operating current.
  2. 2At maximum input and no load, R_s must not let the Zener exceed its power rating.
  3. 3Those two conditions pull in opposite directions.
  4. 4If no resistor value satisfies both, the design needs a different topology — not a bigger Zener.

Why it regulates poorly

  • The knee is steep but not vertical. Its slope is the Zener impedance r_z, a few ohms to tens of ohms, so load changes move the output.
  • The surplus power is always burned as heat, so efficiency is poor and worst at light load.
  • The breakdown voltage itself has a tolerance, typically ±5%, and drifts with temperature away from 5.6 V.

Using it properly

The fix is to stop asking the Zener to supply the load. Let it set a reference at a few milliamps, and put a pass transistor in the current path with its base following that reference. The output becomes V_z − V_be, and the Zener's own current barely varies, so r_z stops mattering.

That circuit is the ancestor of every three-terminal regulator IC. Wrapping an op-amp around the same idea removes almost all the remaining sag.

Where it is genuinely good

As an overvoltage clamp the Zener sits idle and dissipates nothing until a spike arrives — so efficiency and impedance are irrelevant. That is why Zeners and their faster relatives, TVS diodes, appear on almost every exposed input of a real product. It is the same device judged against a completely different requirement.

The numbers you will be asked for

Series resistor

R_s = (V_in − V_z) / (I_z + I_load)

Zener dissipation

P_z = V_z · I_z

worst at no load

Output with load change

ΔV_out = r_z · ΔI_z

Emitter-follower regulator

V_out = V_z − V_be

Watch it work

loading visualisation…

Check yourself

question 1 / 4

One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.

When does a Zener shunt regulator dissipate the most power?
Why do precision voltage references cluster around 5.6 V?
The output of a Zener regulator sags as the load current rises. Why?
A Zener sits on a product's input as an overvoltage clamp. Do its poor regulation and efficiency matter?

0 / 4

4 still unanswered — the dots above jump straight to them.