Zener Diodes and Voltage Regulation
A diode operated in the region every other topic told you to avoid. It runs hottest at no load, which is the opposite of intuition.
Skip to the animationA Zener diode is operated deliberately in reverse breakdown, where its voltage stays nearly constant over a wide range of current — making it a voltage reference, though a poor regulator, because its finite slope resistance and constant power dissipation both work against it.
Breakdown, used on purpose
Past the breakdown voltage, reverse current rises almost vertically while the voltage barely changes. For an ordinary diode that is destruction; a Zener is built to survive it, and that near-vertical characteristic is what a voltage reference needs.
Breakdown itself is non-destructive. Heat is what kills the device, so the current must always be limited by an external resistor.
Two mechanisms, one name
| Zener breakdown | Avalanche breakdown | |
|---|---|---|
| Voltage range | Below about 5 V | Above about 5 V |
| Mechanism | Field pulls carriers out of bonds | Carriers accelerate and knock others loose |
| Doping | Heavy, thin depletion region | Lighter, wide region |
| Temperature coefficient | Negative | Positive |
Around 5.6 V the two coefficients cancel, which is why precision voltage references cluster at that value.
The shunt regulator
A series resistor drops the surplus voltage and the Zener clamps what remains. The resistor's current splits between the load and the Zener, so the Zener absorbs whatever the load does not take — meaning it dissipates most at no load.
- 1At minimum input and maximum load, R_s must still leave the Zener its minimum operating current.
- 2At maximum input and no load, R_s must not let the Zener exceed its power rating.
- 3Those two conditions pull in opposite directions.
- 4If no resistor value satisfies both, the design needs a different topology — not a bigger Zener.
Why it regulates poorly
- The knee is steep but not vertical. Its slope is the Zener impedance r_z, a few ohms to tens of ohms, so load changes move the output.
- The surplus power is always burned as heat, so efficiency is poor and worst at light load.
- The breakdown voltage itself has a tolerance, typically ±5%, and drifts with temperature away from 5.6 V.
Using it properly
The fix is to stop asking the Zener to supply the load. Let it set a reference at a few milliamps, and put a pass transistor in the current path with its base following that reference. The output becomes V_z − V_be, and the Zener's own current barely varies, so r_z stops mattering.
That circuit is the ancestor of every three-terminal regulator IC. Wrapping an op-amp around the same idea removes almost all the remaining sag.
Where it is genuinely good
As an overvoltage clamp the Zener sits idle and dissipates nothing until a spike arrives — so efficiency and impedance are irrelevant. That is why Zeners and their faster relatives, TVS diodes, appear on almost every exposed input of a real product. It is the same device judged against a completely different requirement.
The numbers you will be asked for
- Series resistor
R_s = (V_in − V_z) / (I_z + I_load)
- Zener dissipation
P_z = V_z · I_z
worst at no load
- Output with load change
ΔV_out = r_z · ΔI_z
- Emitter-follower regulator
V_out = V_z − V_be
Watch it work
Check yourself
question 1 / 4
One question at a time. Pick an answer to see why it is right or wrong, then move on — there is no score to keep and nothing is saved.